In Arkham Origins, the Joker will be voiced by Troy. Along with Bane, Joker is the leader of one of the two playable gangs in the Multiplayer game modes. Players can let the Joker in the match Go towards the Lacey Towers' exit. Take your time because, after several moments, you will encounter, for the first time, an enemy with a shield. To deprive this kind of enemies of their shields, you first need to stun them with your cape and "trample" them by double-tapping the key/button displayed on the screen (the above screenshot). While blinded, Batman is unable to move; essentially, the fight from here on out is all about timing. Wait until you see the glint of Catwoman's red goggles and hear the distinctive "shink!" His final phase might as well be a full-blown quick-time event. Any time you attempt to hit him you're thrown into a cutscene where you need to counter between one and three times. After a while In Batman: Arkham Origins ' narrative, Bane ascertains Batman’s true identity and uses it to find the Batcave, where he goads Batman by murdering Alfred. Bane actually wants Batman to kill him Advertisement. The story starts with a simple premise: a series of assassins attempt to end Batman's life. You know, just another day for the Dark Knight. By the end of the saga, he's become a renowned and feared shadow of the night, clearing Gotham of every major criminal overlord in a single night. And then, IIRC, doing the extreme ranked/custom maps unlocks the extreme challenge campaign maps. It says on the locked maps something along the lines of "Complete the appropriate challenges to unlock this challenge." That's because you need to beat the campaign maps, and it unlocks the extreme versions. marden Apr 6, 2014 @ 4:22am. Yeah, that's pretty much it. Enigma quest ends with you destroying his server, collecting all the datapacks is just for you. Once you clear the map all you have left is Alfred's repeating lines unfortunately. I gotta say beating Enigma in this game is even more flacid than what we got in Asylum. ns8jF0.